F(3)=5x^2+4x+9

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Solution for F(3)=5x^2+4x+9 equation: 



(3)=5F^2+4F+9

We move all terms to the left:

(3)-(5F^2+4F+9)=0

We get rid of parentheses

-5F^2-4F-9+3=0

We add all the numbers together, and all the variables

-5F^2-4F-6=0

a = -5; b = -4; c = -6;
Δ = b2-4ac
Δ = -42-4·(-5)·(-6)
Δ = -104
Delta is less than zero, so there is no solution for the equation

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